‫Finally, let's take one more example, and that will be your exercise again, you have the same bowl
‫and you have the same force that points at an angle of 30 degrees like this.
‫And the magnitude of the force vector is five Newtons.
‫However, now we will add one more force that points down, and it's the force of gravity and the force
‫of gravity is equal to the vertical component of this applied force.
‫So the vertical component of this applied force would be the force vector magnitude times sine thirty
‫degrees.
‫And that means that the gravity force is minus five times sine thirty degrees.
‫Because this thing here, don't forget it's five Newtons.
‫And of course this applied force also has a horizontal component, which is this one, and it's the
‫magnitude of the force times cosine.
‫Thirty degrees.
‫So five times cosine.
‫Thirty degrees.
‫So you have two forces here, this one the Applied Force and you have the gravity force that points
‫down, which is equal to the vertical component of the applied force.
‫And now your job is to compute the total work done in this system.
‫What's the total work in the system?
‫And of course, in order to compute the work, you need to know how the ball has moved.
‫So the ball has moved from here to here, a horizontal distance and the distance that it has moved is
‫20 times cosine, 30 degrees meters.
‫But it makes sense that the ball has only moved horizontally because the vertical forces there are equal,
‫but they are in the opposite direction.
‫So the gravity force is cancelled by the vertical component of the applied force.
‫So there is no way that this floating ball can move in a vertical direction.
‫It can't go up.
‫It can go down.
‫However, the horizontal component of the supplied force will move the ball from this point to this
‫point, and the distance is 20 times cosine, 30 degrees meters.
‫So with that in mind, try to compute the total work in this system.
‫See you in the next video.