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‫Welcome back.

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‫Let's now compute the Phi Beta and then the two variables, let's derive formulas for them.

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‫The hints that I gave you were the following.

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‫You should first put the equations in this form and in this form.

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‫So if you're Z double that equals all that, then you're a Z, double that plus G equals cosine five

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‫times cosine theta times you one over the mass of the drone.

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‫So X double dot over a Z double that plus G equals this equation here, which is the X double date equation

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‫here divided by this equation here.

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‫So you can cancel out this and this, you can then separate this equation like this and then you can

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‫cancel out this cosine phi with this cosine phi here.

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‫Now from trigonometric identities, you know that sine X divided by cosine X equals tangent X, that

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‫means that this part here sine theta over cosine Seeta.

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‫That will be your tangent theta like this and then also sine phi over cosine phi.

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‫This will be your tangent phi like this.

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‫So I can rewrite this entire equation like this.

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‫Similarly, why doubled that over a double Dods plus GS would be this equation here divided by this

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‫equation here and you can see it here and now you can also cancel out you one over M and you one over

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‫M.

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‫You can then separate this equation in the same way and then you can cancel out counseling fi here and

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‫counseling FI here again here, you will have signed Seeta over Cosine Theta and that will be your Tenjin

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‫Seeta.

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‫And then here you will have signed Phi Overconsume Phi and that will be your Tenjin Phi.

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‫And so in the end this equation looks like this.

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‫That's your end result.

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‫And so in the end, you have these two equations here, so you have X, double dot over Z, double that,

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‫plus it equals all this and then Y, double dot over Z, double that, plus G, it equals all this.

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‫And now let's make a couple of abbreviations to write less.

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‫Let's say that this thing here is a.

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‫Then let's say that this thing here is B, so X double date over the plus G equals A and Y, double

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‫date over Z, double that plus G equals B, then let's say that cosine Sysop R equals C, and therefore

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‫this is C and this is also C and then sine Sysop R equals D, so this one here is D and then also this

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‫one here is also D.

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‫In that case, the first equation can be rewritten like this, a equals tangent theta times C like you

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‫can see here plus.

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‫Tangent five times D divided by cosine Seeta.

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‫That's this first equation here, and then the second equation would be B equals tangent three times

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‫D minus tangent five times C divided by cosine theta like this.

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‫That would be your second equation here.

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‫And so if I take these equations here, then I can rearrange them like this, I can take this term here

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‫and then I can put it on the other side of the equation sine like this.

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‫And then here I can take this term and then I can put it on the other side of the equation sine and

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‫then I can take this B and then I can put it here on the other side of this equation.

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‫Sine if I do that then here I will have tangent five times D over cosine Seeta which is this term here

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‫equals a minus tangent Theta times C and then here I will have tangent five times C or Cosine Seeta,

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‫which is this one here, and that equals tangent theta times D minus B.

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‫I now want to express this tension phi in terms of everything else.

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‫So Tangent Phi equals this term here and then I'm going to multiply it by cosine theta.

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‫So this cosine theta will come here now and then I'm going to take this D and then I'm going to divide

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‫this entire thing by D and I can do the same thing here.

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‫I want to express this tension phi in terms of everything else.

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‫So I'm going to do it like this tangent phi equals tangent theta times D minus B, that's this term

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‫here.

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‫And I'm going to multiply by this cosine Seeta and then I'm going to divide all that by C like this.

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‫And now, look, you've got tension fire here and you've got tension fire here they are the same thing

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‫like tangent five equals tangent fire like this.

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‫Therefore, these two expressions here, they are equal to each other.

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‫They are written in a different form, but they are the same thing.

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‫And since they are equal to each other, then I can get rid of this cosine sheeter and this cosine Seeta.

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‫And now I'm going to separate this equation like this, a over deed, so this divided by this minus

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‫and then you will have Danjean Theta time C over D, and that equals tangent times D over C, so it's

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‫here tension theta times the over C minus B over C is here, minus B oversee.

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‫I can rearrange the terms and then I will have A over D plus B over C equals.

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‫And then on the other side I will have tangent theta and then since I have to tension setas here and

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‫this one will go on the other side of the equation sine then I can factor out tension theta and I will

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‫have here D over C plus C over D, so I multiply my tension theta by this expression here and now I

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‫can express tension theta in terms of everything else.

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‫Tangent theta equals.

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‫A over, D plus B over, see, that's this one here.

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‫Divided this thing here, D.R.C., plus C over D like this.

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‫We can now take this A over D plus B, oversee this numerator and we can see that.

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‫This numerator here equals A time C plus B times D, divided by D, time C, so you just take the common

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‫denominator and this is what you will get.

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‫And then you can take this other expression, D over C plus C over D, and if you take the common denominator,

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‫then you will have D squared plus C squared divided by D times C.

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‫That means that this expression here can be rewritten like this.

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‫So this numerator in this form will be divided by this denominator in this form here and of course,

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‫you can cancel out the disks here and here and you're left with a time C plus B times D divided by.

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‫D squared plus C squared.

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‫And now what is D squared plus C squared?

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‫Well, D squared plus C squared equals sine PSI sub R squared, plus cosine sysop r and that is also

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‫squared because your deal was signed.

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‫Sysop are in your C was cosine sysop r and this is also a trigonometric identity.

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‫This trigonometric identities will equal one and that means that this denominator here will be one.

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‫And that means that your tangent theta equals eight times C plus B times D.

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‫In other words, your theta will be the arc tangent or the inverse tangent of eight times C plus B times

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‫D.

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‫And so if you replace all these letters here, then this is what you will have in the end, your theta

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‫equals your inverse tangent and then all this.

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‫So you have your theta.

