Hello. 1
Let's continue. 2
to questions and answers part 4. 3
Let's take a look. 4
The question one How to two wire PT100 connection and answer the correct connection type is as shown 5
on the two wire line then connecting your sensor to the L+ and L- terminals you must bridge 6
the L- an I- terminals between themselves in here you can see three wire connection 7
in three way connection in here. 8
We have a bridge. 9
So I- is not connected to L- in here. 10
So for three wire L+ and L- and I- can connect to separately. 11
But for two wire for example for the PT1000 you can connect to L+ to and L+ connection 12
after you connect your L- connection you need to put a bridge to here for I- connection this 13
is how to wire PT100 or PT1000 connection as to wire or three wire question 2 how do I 14
direct the high speed input to the high speed output is it possible for example we are reading the pulses 15
coming from encoder to my input and suddenly from my output we are sending these pulses directly. 16
Is it possible. 17
So let's take a look at our answer the time to read the logic input differs within the plcs scan 18
time cycle also the reading filter time of the inputs is 10milliseconds at the default settings it 19
is set. 20
This means that you cannot read an input below 10 milliseconds and activate the output contact at the 21
same time. 22
If your plc scan time is over 10 milliseconds it also means that you cannot operate under this cycle 23
time period. 24
So let's take a look. 25
to question 3. 26
I want to run a pid controlled hydrofor with the VFD series driver. 27
We have driver means VFD we have 4 to 20 mA ten bar pressure sensor is there an example with 28
connection. 29
scheme or parameter explanations with application. 30
Let's take a look. 31
to answers and our scheme for VFD-E PID settings parameter ten to 10.00 for PID set 32
point selection we can enter the PID set value to parameter 10.11 by setting the parameter 33
10.00 from 10.04 and or enter it as desired from the parameter 2.00 parameter by setting 34
the parameter 10.00 to 1, parameter 10.01 for PID feedback input terminal. 35
So in here PID feedback input negative feedback ACI set to 4 to 20mA that we can do it 36
in here 10.02, 1.0 factory value proportional gain it should be determined and 37
adjusted according to the characteristics of the system 10.03 is 1.00 38
factory value of integral time ,it should be determined and adjusted according to characteristics 39
of the system 10.04 40
Is it close to 0.00 41
So this is factory value of derivative control. 42
It should be determined and adjusted according to characteristics of the system also. 43
10.11 44
equals to 12.5 PID setpoint source after selecting 10.00 parameter 45
As for PID set value is entered from this parameter in here we have a fuse or circuit breaker and 46
in here we have VFD-E and in here our motor connection and you can see in here acı-acm for 4-20mA 47
4-20mA 48
This outputs current outputs can be used like this with these parameters after you adopt these parameters 49
PID set points selections and etc. 50
This can be used but in here I need to correct one thing we will use this 4-20mA 51
10 bar pressure sensor. 52
This one for the control this motor. 53
So we are not sending analog outputs to here. 54
Here we are getting analog inputs from here to my VFD-E and we are turning our motors according to 55
these analog inputs to inside of my VFD or drive. 56
Question 4 how to reset from Z phase with 3600 pulse rotary encoder I connected phases are A and B 57
and Z to the physical inputs x0,X1 x2 respectively I counted down and up with the C251 58
x251 59
How can I perform the reset by catching the Z phase while the motor is returning. 60
I would be glad if you could help plc model is that DVP12SA2 , answer is that if the 61
aim is to reset the counter value in each z phase the encoder is using C252 number in here you can 62
see for example in question the user or customer said x 0 X1 and X2 is used, 63
I am going to ride side from here okay. 64
We will go up and down or a and b phase a input on phase b input is used and up and downs. 65
Okay but also we need to reset for example in our application. 66
We need to reset something else that's okay. 67
So when we can use or we need to use two phase two input a counter C252, x0 is a phase X1 68
is B phase x 4 is Z phase 69
So 70
what was the question. 71
So in here how can I perform the reset by catching the Z phase while the motor is returning. 72
So if you use not C251 counter because in here there is no reset condition but if you connect your 73
x4 in here Z is connected to here. 74
Okay. 75
And when x 4 is goes high my C252 counters becomes reset. 76
So it can be solution of this question and in here. 77
Question again encoder 3600 pass but reset it at 14400 pulse 78
What is the reason for this problem in X2 interrupt. 79
I can reset from Z phase ,Z phase with the C251 counter. 80
There was no different situation with the C252 counter. 81
So answer is that 3600 x 4 =14400 82
If you write one in D1122 you will read 3600 pulse encoder 83
as three thousand six hundred. 84
Remember there were core efficient value of the encoders. 85
So for example if your encoder coefficient value is 1 and is your encoder is for example 86
let's say 3600 so you will reach to Z phase after 3600 pulse 87
but your coefficient value is let's say 2 , you will get this Z phase or you will get complete turn 88
after 7200 pulse so and M1002 89
This is the first second contact. 90
It is moving to k 2 to D1022 example and we are multiplying our encoder value by 2 and we are reaching 91
to Z phase after 7200 pulse for example. 92
So if this value if your encoder value is increasing too for example 14400 93
pulses and you are still waiting your Z phase. 94
You need to check D1022 immediately if it is not equals one. 95
You can change it or you can check it. 96
And according to your value in D1022 you can continue to your project or programming and in here 97
we have another one question. 98
I want to read 4 -20 current with the DTC 1000. 99
I found that the jumper positions should be changed in the document but I couldn't find the jumper location 100
on DTC 1000. 101
Where can I find these. 102
So answer is that two sockets marked in the picture next to the terminal connection point of the DTC 103
1000 module must be bridged with a jumper or different connection tool. 104
In here you can see it. 105
This two. 106
How can I say inputs or this two connection points must be bridge with the jumper or you can you can 107
connect it these things together with a different connection tool. 108
So for example I want to read 0-10 VDC analog value with the DTC 1000 module but I couldn't find 109
a very clear source. 110
Can you help the plc that I use is 14SS2 and the DTC 1000 is bridged that moment. 111
What should we do answer is that when connecting to 0-10 what to DTC the bridge inside , should 112
not be connected for the 0-10 VDC it is not necessary to jumper put the jumper or bridge these 113
connection points for current or 4-20mA current. 114
If you want to work with the current you need to use jumper or unit to connect this connection point 115
altogether. 116
But for the 0-10 volts DC you don't need a bridge and that bridge is for just current input on 117
a simplified connect to analog input to + and - input. 118
That's all. 119
And then you can run or you can use your DTC as 0-10 volt analog value. 120
So for this video I am finished here. 121
See you in the next video.